The first five ionization energies of an unknown element are listed in the table above. Which of the following statements correctly identifies the element and cites the evidence supporting the identification?
The first five ionization energies of an unknown element are listed in the table above. Which of the following statements correctly identifies the element and cites the evidence supporting the identification?

The first five ionization energies of an unknown element are listed in the table above. Which of the following statements correctly identifies the element and cites the evidence supporting the identification?

(A) Na, because of the large difference between the first and the second ionization energies
(B) Al, because of the large difference between the third and fourth ionization energies
(C) Si, because the fifth ionization energy has the greatest value
(D) P, because a neutral atom of P has five valence electrons

SOLUTION:
In order to predict the element correctly, we need to find the greatest jump in ionization energy. In this case, we can see that the largest increase is from the third to the fourth ionization energy. This means that the element must be in group 3 on the Periodic Table. Choice B is the correct answer choice.
The large jump from third to fourth ionization energy for aluminum is due to aluminum having 3 valence electrons. Once 3 valence electrons are lost, aluminum gains a noble gas configuration and is stable. Taking the fourth electron from aluminum is much harder resulting the big jump from the third to the fourth ionization energy.

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