What is the value of Kb for the formate anion, HCOO–? Ка(HCOOH) = 2.1 × 10-4
Solution:
The equation that is needed to solve this problem is Ka*Kb= 1.0 *10-14 (at 25C), where Ka is the equilibrium constant of an acid and Kb is the equilibrium constant of its conjugate base.
Let’s plug in the values to get the answer.
2.1 × 10-4*Kb =1.0*10-14
Kb = 4.8×10-11
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