What is the value of Kb for the formate anion, HCOO-? Ка(HCOOH) = 2.1 × 10-4
What is the value of Kb for the formate anion, HCOO–? Ка(HCOOH) = 2.1 × 10-4 Solution:The equation that is needed to solve this problem is Ka*Kb= 1.0 *10-14 (at 25C), where Ka is the equilibrium constant of an acid and Kb is the equilibrium constant of its conjugate base. Let’s plug in the values…
