Given the two reactions:
CuCI(s) + Cl–(aq) ⇋[CuCI2]–(aq) K= 5.2×10-2
Cu+ (aq) + 2Cl–(aq)⇋ [CuCI2]–(aq) Kf= 3.0×105
What is the value of Ksp for CuCI?
Solution: Ksp is the solubility product equilibrium constant. To write the Ksp expression, first you need to write an equation where ionic solid is on the reactant side and aqueous ions it dissociates into are on the product side. CuCl(s)⇋Cu+ (aq) + Cl–(aq).
You need to add to equations in such a way as to get the final equation: CuCl(s)⇋Cu+ (aq) + Cl–(aq). To do this, you can keep the first equation and reverse the second equation. Remember, when reversing an equation you need to take the reciprocal of K.
CuCI(s) + Cl–(aq) ⇋[CuCI2]–(aq) K= 5.2×10-2
[CuCI2]–(aq) ⇋Cu+ (aq) + 2Cl–(aq) new K = 1/Kf
New equation: CuCl(s)⇋Cu+ (aq) + Cl–(aq)
To get the new K, you need to multiply K’s of the steps you’re adding. Ksp = K(1/Kf) = K/Kf
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